Animals Icons Crack ...Q: Don't count changes in load I am trying to figure out if there is any way to not count the value of my store in the load and remove the products in a new loop. Basically i am trying to do this: var newProductsArray = [], storeProductsArray = [], oneMore = 1; store.forEach(function(product) { oneMore = 1; product.forEach(function(stock) { oneMore = 0; }) newProductsArray.push(product); }) But i think this would take a lot of time and i will only need 5 products of 30. I have been trying with Promise but no luck. Thanks! 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If you look at Vector, you'll see that it's an array, and that its index values are 0-based. That is, the first element is at index 0, and so on. So to get the ith element of a vector, you have to do: Vector a = b.take(10) Vector[] a = a.array() a[i] = b.get(i); I can use an index from a Range to get the result, but I have to pass it to a method that takes an index. As ranges are lazy, I'll actually create the vector and get a Range before I do anything else with it. const Vector a = b.take(10); const Range index = Range::new(0, a.length); a.get(index); To get $b$, I do the same: const Vector a = b.take(10); const Range index = Range::new(0, a.length); a.get(index); const Vector b = b.take(index.end); That's the code I use, it's the same in a real function. Notice the order of the constructor calls. The original is: static Vector constructor(Vector b) { return b.vector(b.length, 0); } This initializes the vector by defining the length, and then calling the constructor on the right. 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